ABC is a right angled triangle. AB=12 cm, BC=5 cm.What is the length of radius of the circle inscribed the triangle ???
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first of all we have to use formula
AB+BC-AC/2 we will get answer
AB+BC-AC/2 we will get answer
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The length of radius of the circle inscribed the triangle is AC/2
AC = √ ( AB^2 + BC^2 )
= √(12^2 + 5^2)
= √( 144+25)
= √169
= 13 cm
AC/2= 13/2
= 6.5cm
AC = √ ( AB^2 + BC^2 )
= √(12^2 + 5^2)
= √( 144+25)
= √169
= 13 cm
AC/2= 13/2
= 6.5cm
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