Question

ABC is a right angled triangle calculate the magnitude of force on charge minus q.
plse solve for me​

Answer 1

Answer:

Explanation:

Using Pythagoras theorem:

AC = SqRoot (5a)2 - (3a)2

AC = SqRoot (16a)2

AC = 9a

Force 1 = (K*Q*9Q)/(3a)2

Force 1 = 9KQ2/9A2

Force 1 = KQ2/A2

Force 2 = (K*Q*16Q)/(4a)2

Force 2 = 16KQ2/16A2

Force 2 = KQ2/A2

Net Force = SqRoot (Force1)2 + (Force2)2

                 = (2Force)2  ..............    [Force 1 = Force 2]

                 = SqRoot 2 * Force

                 = SqRoot 2 * (KQ2/A2)

Answer 2

Answer: √2 kQ²/a²

F = √2 KQ²/a²