Question

ABC is a right angled triangle in which angle A = 90° and AB = C . find angle B and angle C ​

Answer 1

Answer:

Step-by-step explanation:

Given,

∠A = 90° and AB = AC

A/q,

AB = AC

⇒ ∠B = ∠C (Angles opposite to the equal sides are equal.)

Now,

∠A + ∠B + ∠C = 180° (Sum of the interior angles of the triangle.)

⇒ 90° + 2∠B = 180°

⇒ 2∠B = 90°

⇒ ∠B = 45°

Thus, ∠B = ∠C = 45°

Answer 2

$\huge \mathbb \red{ANSWER: }$

Since AB=AC,

So, △ABC is Right-angled isosceles.

∠B=∠C ...(angles opp. to equal sides are equal)

∠A+∠B+∠C=180∘ ...(angle - sum property of a triangle)

Substituting ∠B=∠C, ∠A=90°

90° +2∠B=180°

2∠B=180° –90° =90°

⇒∠B=45°

So, ∠C=∠B=45°.