Math, asked by sanidhya767, 11 months ago

ABC is a right angled triangle in which angle b is equal to 90 degree and a b is equal to AC find Angle B and angle C 9 standard mathematics textbook exercise 5.2 7th question​

Answers

Answered by AwesomeSoul47
6

Answer:

side ab=side ac

angle b = 90degree

c = 45 degree

Answered by ansari3390
0

Step-by-step explanation:

ABC is a right angled triangle (given)

Here ∠A = 90°                          (given)

And AB = AC                            (given)

So,

ΔABC is an right isosceles triangle in which ∠A = 90° and AB = BC

So, ∠B = ∠C       [∵ AB = BC]

To be found :

∠B and ∠C

Now,

We know that,

Sum of all interior angles of a triangle is 180°

So,

In triangle ABC,

∠A + ∠B + ∠C = 180°

⇒ 90° + ∠B + ∠B = 180°   [As ∠B = ∠C, we can write ∠B in place of ∠C ]

⇒ 90° + 2 ∠B = 180°

⇒ 2 ∠B = 180° - 90°

⇒ 2 ∠B = 90°

⇒ ∠B = 90° ÷ 2

⇒ ∠B = 45°

Therefore,

∠C = 45°      [ as ∠B = ∠C, and ∠B = 45° ]

Hence,

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