ABC is a right angled triangle in which angle b is equal to 90 degree and a b is equal to AC find Angle B and angle C 9 standard mathematics textbook exercise 5.2 7th question
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Answered by
6
Answer:
side ab=side ac
angle b = 90degree
c = 45 degree
Answered by
0
Step-by-step explanation:
ABC is a right angled triangle (given)
Here ∠A = 90° (given)
And AB = AC (given)
So,
ΔABC is an right isosceles triangle in which ∠A = 90° and AB = BC
So, ∠B = ∠C [∵ AB = BC]
To be found :
∠B and ∠C
Now,
We know that,
Sum of all interior angles of a triangle is 180°
So,
In triangle ABC,
∠A + ∠B + ∠C = 180°
⇒ 90° + ∠B + ∠B = 180° [As ∠B = ∠C, we can write ∠B in place of ∠C ]
⇒ 90° + 2 ∠B = 180°
⇒ 2 ∠B = 180° - 90°
⇒ 2 ∠B = 90°
⇒ ∠B = 90° ÷ 2
⇒ ∠B = 45°
Therefore,
∠C = 45° [ as ∠B = ∠C, and ∠B = 45° ]
Hence,
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