ABC is a right angled triangle, right angled at A. a circle is inscribed in it. the length of two sodes containing angle A is 12 cm and 5 cm. find the radius.
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Thus,radius of the circle is 2cm...
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hmm...your method is also right
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So hypotenuse=√(12^2+5^2)
=√169
=13
Naw radius=a+b-c/2
=(12+5-13)/2
=4/2=2 cm