factorise by splitting the middle term 12x^2-7x+1
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Answered by
3
-12x2 + 7x - 1 = -1 • (12x2 - 7x + 1)
Trying to factor by splitting the middle term
3.2 Factoring 12x2 - 7x + 1
The first term is, 12x2 its coefficient is 12 .
The middle term is, -7x its coefficient is -7 .
The last term, "the constant", is +1
Step-1 : Multiply the coefficient of the first term by the constant 12 • 1 = 12
Step-2 : Find two factors of 12 whose sum equals the coefficient of the middle term, which is -7 .
-12
+
-1
=
-13
-6
+
-2
=
-8
-4
+
-3
=
-7
Trying to factor by splitting the middle term
3.2 Factoring 12x2 - 7x + 1
The first term is, 12x2 its coefficient is 12 .
The middle term is, -7x its coefficient is -7 .
The last term, "the constant", is +1
Step-1 : Multiply the coefficient of the first term by the constant 12 • 1 = 12
Step-2 : Find two factors of 12 whose sum equals the coefficient of the middle term, which is -7 .
-12
+
-1
=
-13
-6
+
-2
=
-8
-4
+
-3
=
-7
Answered by
8
...... Ur answer .........
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