ABC IS A RIGHT ANGLED TRIANGLE RIGHT ANGLED AT B BC=BA.D IS A POINT ON AC PRODUCED AND A LINE DEF CUTS CB AT E,AB AT F. IF ANGLE D IS 13 DEGREE AND ANGLE FAE =29 DEGREE THEN THE MEASURE OF ANGLE FEA IS ?
Answers
Answer:
we are given
A diagram consists of three triangles ABC, ACD, and ADE – all of them are individually isosceles right triangles.
The area of ΔABC is 6.
To Find
We need to determine
The area of ΔADE.
Approach & Working
Let us assume the length of AB = n
As ΔABC is an isosceles right angle triangle, AB = BC = n
Therefore, AC = √(n2 + n2) = √2n
We also know that ΔACD is an isosceles right angle triangle.
Hence, AC = CD = √2n
Therefore, AD = √(2n2 + 2n2) = 2n
Finally, ΔADE is an isosceles right-angle triangle.
Hence, AD = DE = 2n
Thus, the area of ΔADE = ½ * 2n * 2n = 2n2
We are also given that area of ΔABC is 6.
Step-by-step explanation:
❖Question:-
BC is a right triangle, right angled at B. BC = BA. D is a point on AC produced and a line DEF cuts CB at E, AB at F. IF ZD = 13º and ZFAE = 29, then
❖Solution :-
We are given,
A diagram consists of three triangles ABC ,ACD & ADC - all of them are individually as I isosceles right triangles.
The area of ∆ ABC = 6
You need to determine
The area of ∆ ADE
Approach and working
Let us assume the length of AB = n
As ABC is an isosceles right angle triangle ,AB = BC = n
Therefore, AC = √(n2+2n2) = 2n
we also know that ∆ADE is is an isosceles right angle triangle
hence, AD = DE = 2n
Thus, the area of ∆ADE = 1/2 × 2n × 2n = 2n2
We are also given that area of ∆ABC = 6
.
Hope it helpful .☺