Question

ABC is a right angled triangle with angle ACB = 90° , BC = 12 cm , AB = 15 cm and CD = 5 cm. Find the lengths of BD and AD.​

plzz answer this ....

Answer 1

ANSWERS

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Answers

In Triangle BDC

BD²= BC²+CD²

BD² = 12² + 5²

BD² = 144 +25

BD² = 169

BD = 13cm

In Triangle ABC

AB²= AC² + BC²

15² = AC² + 12²

225 = AC² + 144

AC² = 225 - 144

AC² = 81

AC = 9

so,AC = AD + CD

9 = AD + 5

AD = 9-5

AD = 4

Hence,BD=13cm ; AD=4cm

Answer 2

Step-by-step explanation:

Given:

In Right angle triangle BDC

(BD)

b * d ^ 2 = b * c ^ 2 + c * d ^ 2

b * d ^ 2 = 12 ^ 2 + 5 ^ 2 b * d ^ 2 = 144 + 25

b * d ^ 2 = 169

b * d ^ 2 = 13 ^ 2

sq cut from sq bd = 13

hence bd = 13

In right angle triangle BAD

b * a ^ 2 = b * d ^ 2 + a * d ^ 2 15 ^ 2 = 13 ^ 2 + a * d ^ 2

225 = 169 + a * d ^ 2 225 - 169 = a * d ^ 2

56 = a * d ^ 2

sqrt(56) = ad 2sqrt(14) * cm = ad