Math, asked by susantashit3233, 10 months ago

ABC is a right triangle C=90. AE and BD are two medians of a triangle ABC meeting at F. The ratio of the area of ABF and the quadrilateral FDCE.

Answers

Answered by lavanyax

1

Step-by-step explanation:

apply ar of quad.(FDCE)/at of Tri(ABF)=1/2xbxh/bxh

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