Abc is a right triangle right angle at c and d is midpoint ofbc .Prove that ab×ab=4 (ad×ad)-3ac×ac.
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Step-by-step explanation:
In right tri adc
Ad^2=ac^2+cd^2
Ad^2=ac^2+(bc/2)^2. (D is midpoint of bc)
4ad^2=4ac^2 +bc^2
Bc^2=4ad^2-4ac^2. --- eq-1
In tri abc
Ab^2 =bc^2 +ac^2
Ab^2 =ac^2+4ad^2-4ac^2.
Ab^2=4ad^2 -3ac^2
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