Question

find the area of a triangle whose sides are 3cm 4cm and 5cm

Answer 1

Here is your answer

sides are 3cm , 4cm and 5cm.

let a = 3 cm , b = 4 cm and c = 5 cm

semi perimeter ( s ) = 1/2 × ( a + b + c ) = 1/2 × (3+4+5) = 1/2 × 12 = 6 cm

s-a = 6 - 3 = 3 cm
s-b = 6-4 = 2 cm
s - c = 6-5 = 1 cm

therefore
area of triangle. = under root s ( s-a)(s-b)(s-c ) = under root 6* 3* 2 * 1
= ✓36 = 6 cm².

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Answer 2

$\textbf{Answer :}$

The sides of the triangle are 3 cm, 4 cm and 5 cm

Here, 3² + 4²

= 9 + 16

= 25

= 5²

By Pythagoras theorem, the given triangle is right-angled whose base = 3 cm, height = 4 cm and hypotenuse = 5 cm

Therefore, the area of the given triangle

= 1/2 × base × height

= (1/2 × 3 × 4) cm²

= (3 × 2) cm²

= 6 cm²

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