Abc is a right triangle right angled at b if bc=7cm and ac-ab=1cm find cosa+sina
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ac-ab=1cm
ac= 1+ab
by Pythagoras Theorem
ac^2=ab^2+bc^2
(1+ab)^2=ab^2 +(7)^2
1+ab^2+2ab= ab^2+49
ab^2-ab^2+2ab=49-1
2ab=48
ab=24
ac=1+ab=1+24=25
cos a=ab/ac=24/25
sin a=bc/ac=7/25
cos a + sin a =7/25+24/25
=7+24/25
=31/25
mark as brainliest please
ac= 1+ab
by Pythagoras Theorem
ac^2=ab^2+bc^2
(1+ab)^2=ab^2 +(7)^2
1+ab^2+2ab= ab^2+49
ab^2-ab^2+2ab=49-1
2ab=48
ab=24
ac=1+ab=1+24=25
cos a=ab/ac=24/25
sin a=bc/ac=7/25
cos a + sin a =7/25+24/25
=7+24/25
=31/25
mark as brainliest please
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Answered by
47
hope it helps
.
..all the best
.
. mark as brainliest pls
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