ABC is a right triangle right angled at B such that BC is equal to 6 cm and a b is equal to 8 cm find the radius of its in circle
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Answer:
the answer is 2 cm
Step-by-step explanation:
AB²+BC²=AC²
8²+6²=AC²
AC²=64+36=100
AC=√100=10
Radius of in circle=area of ∆ABC/Semiperimetre
of ∆ABC
=(½*base*height)/(AB+BC+AC/2)
=(½*8*6)/ (8+6+10/2)
=24/12
=2cm
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