Question

ABC is a right triangle, right angled at C. If A = 30° and AB = 40 units, find the remaining two

sides of ΔABC.​

Answer 1

Answer:...........................................:)

Step-by-step explanation:

Answer 2

Given:-

• ABC is right triangle, right angled at C
• A = 30° ; AB = 40 units

ToFind:-

• The remaining two sides of ∆ABC

Solution:-

We have,

• ∠A + ∠B + ∠C = 180°

→ 30° + ∠B + 90° = 180°

(∵ ∠A = 30° and ∠C = 90°)

→ ∠B = 180° - 120° = 60°

• cosA = AC/AB

→ cos30° = AB/40

→ √3/2 = AC/40

→ AC = √3/2 × 40

→ AC = 20√3 units

• sinA = BC/AB

→ sin30° = BC/40

→ ½ = BC/40

→ BC = 40 × ½

→ BC = 20 units

Hence,

• AC = 20√3 units
• BC = 20 units
• ∠B = 60°