Question

Abc is a straight line find the value of alpha please solve asap

Answer 1

Answer:

answer is this it is correct

Answer 2

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angle CBD=angle CDB ( given that BC=CD)

In ∆CBD

angle BCD=90°

BCD+CBD+CDB=180° (Angle Sum Property of ∆)

90°+2CBD=180°

2CBD=180°-90°=90°

CBD=90°/2=45°

angle CBD=45°

Given that ABC is straight line

${42}^{0} + \alpha + {45}^{0} = {180}^{0}$

$\alpha = {180}^{0} - ( {42}^{0} + {45}^{0} ) \\ \alpha = {180}^{0} - {87}^{0} = {93}^{0}$

Alpha = 93°