Question

abc is a triagle in which altitudes be and cf to sides ac and ab are equal show that 1. triangle abc is congruent to triangle acf 2.ab=ac​

Answer 1

Answer:

⭐Here is your answer⭐

Given That,

ABC is a ∆ in which BE and CF are altitudes.

So that, <AEB= <AFC= 90°

Then To prove that,

∆ABE Congruent to ∆ACF and AB=AC,

Proof:- In ∆ABE and ∆ACF,

<AEB= <AFC= 90°

<A = <A (common)

BE= CF (Given)

∆ABE Congruent to ∆ACF (A.A.S rule)

Hence,

AB=AC (C.P.C.T or Corresponding Parts of Congruent ∆).

Proved