ABC is a triangle D E and F are the midpoints of A B ,AC and BC prove that DE and AF bisect each other
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In triangle ABC
given
D is mid point on AB. so AD=DB
in the same way AE=EC. and. BF=FC
join DE
now triangle ABC~ triangle ADE by sss
Join AF
now in triangle AFB and AFC
AF=AF
angle A= angleA
BF=FC
∆AFB~AFC by SAS
now de and AF bisect each other
given
D is mid point on AB. so AD=DB
in the same way AE=EC. and. BF=FC
join DE
now triangle ABC~ triangle ADE by sss
Join AF
now in triangle AFB and AFC
AF=AF
angle A= angleA
BF=FC
∆AFB~AFC by SAS
now de and AF bisect each other
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4
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