Question

abc is a triangle in which ab equal to ac equal 4cm and angle a equal to 90 degree.calculate the area of angle abc​

Answer 1

Answer:

ofrom given figure,

ABC is an right angled triangle

AD is the perpendicular drawn from point A to the BC

Area of traingle = 1/2 ×base × height

= 1/2× 4×4

= 2× 4

= 8

cm ^{2}cm

2

Now,by pythagoras theorem

( ab)^{2} + (ac) ^{2} = ( bc) ^{2}(ab)

2

+(ac)

2

=(bc)

2

(4)^{2} + (4)^{2}. = (bc)^{2}

16 + 16 = (bc)^{2}

32 =(bc)^{2}

4√2 = bc

perpendicular bisector bisect the segment into two equal parts

hence, AD = 4√2/2

AD = 2√2

therefore the length of the perpendicular is 2√2 cm.