Question

abc is a triangle in which altitudes be and cf to sides ac and ab are equal. show that (i) ∆abe =~ ∆acf (ii) ab = ac

Answer 1

solution:

1) In traingle ABE & ACF

angle AFC= AEB= 90° [Given]

angle BAC= CAB

& BE= CF

SO, ∆ABE=~ ∆ACF [AAS congrency conditions]

2) By c.p.c.t,

AB= AC

______________

Amrit⭐

Answer 2

Answer:

(i) In ABE and ACF,

A= A [Common]

AEB = AFC =  [Given]

BE = CF [Given]

ABE ACF [By ASA congruency]

(ii) Since ABE ACF

BE = CF [By C.P.C.T.]

ABC is an isosceles triangle.

Step-by-step explanation: