AbC is a triangle in which angle B = 2 angle C . D is a point on side BC such that AD bisects angle BAC and AB=BC , prove that Angle BAD=22½
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Answer:
BAD=22½
Step-by-step explanation:
Tringle ABD & ACD
AB=AC (GIVEN)
ANGLE ADB=ANGLE ADC(BOTH ARE RIGHT ANGLES)
AD=AD(COMMON)
SO BOTH THE TRIANGLES ARE CONGRUENT
THEREFORE BD=CD(CPCT)
ANGLE BAD=ANGLE CAD(CPCT)
HENCE AD BISECTS BOTH BC AND ANGLE A
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