Question

Abc is a triangle in which angle b=2angle



c. d is a point on bc such that ad bisect angle bac and ab =dc

Answer 1

in tri. bad and cad
ab= ac
ang. b= ang.c
ad=ad
by s.a.s
ab=dc by c.p.c.t

Answer 2

This was a tricky question in Maths ncert class 9.

Needs just one construction.

In ΔABC, we have,

∠B=2∠C or ∠B=2y where ∠C=y

AD is the bisector of ∠BAC. So, Let ∠BAD=∠CAD=x

Let BP be the bisector of ∠ABC.