Question

ABC is a triangle in which ∠B = ∠C and ray AX bisect the exterior angle DAC. If ∠DAX = 70°, then find ∠ACB

Answer 1

Answer:

70°

Step-by-step explanation:

As described, D must be on the extension of the side AB, going beyond A.

As AX bisects ∠DAC, ∠DAX is half of ∠DAC.  We're told that ∠ DAX is 70 degrees, so∠DAC is 140°.  Since DAB is a straight line, the angles∠ DAC and ∠CAB add up to 180°.  So

angle CAB = 180 - ∠ DAC = 180°- 140 = 40°

Since the angles in a triangle add up to 180 °, we have

∠CAB +∠ ACB + ∠ ABC = 180°

so

∠ ACB +∠ABC = 180 -∠CAB = 180° - 40° = 140°

We're also told that angles ∠ACB and ∠ABC are equal, so the above equation tells us that

∠ ACB = 70°

Answer 2

Step-by-step explanation:

here you go thank you