ABC is a triangle in which DE || BC , find <A
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Answer:
/_A = 35°
Step-by-step explanation:
In ∆BCE,
80° + 30° + /_C = 180°
/_C = 180° - 110° = 70°
Since, DE || BC & BE is transversal,
Therefore, /_EBC = /_DEB = 30°
hence, /_DEC = 80° + 30° = 110°
Now, in quadrilateral DBCE,
/_D + /_B + /_E + /_C = 360° (Angle Sum Property)
105° + /_B + 110° + 70° = 360°
/_B = 360° - 285° = 75°
Now, in ∆ABC
/_A + /_B + /_C = 180° (Angle Sum Property)
/_A + 75° + 70° = 180°
/_A = 180° - 145° = 35°
Hope it helps!!
Have a great day!!
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