Abc is a triangle, right angle at c and p is the length of the perpendicular drawn from c to ab. By expressing the area of the triangle in two ways show that (i) pc =ab (ii) 1 /p2 = 1/a2 +1/b2
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1.Area is 1/2 base * height . So for the same triangle area can be 1/2*b*a and can be 1/2*p*c. Hence cp = ab
2 . From above p2 = a2b2/c2
1/p2 = c2/ a2b2
but for right triangle c2 = a2 +b2
Hence 1/p2 = (a2+b2)/ a2b2
Hence 1/p2 = 1/a2+1/b2
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