Abc is right angled triangle at b such that bc=6cm and ab=8cm find the radius of its in circle
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Answer: 2 cm
Step-by-step explanation:
AC = (Pythagoras Theorem) = √(6² +8²) = 10cm \
Radius of the incircle = area/semi perimeter
Area of the triangle = 1/2*b*h = 1/2*6*8 = 24cm²
semi perimeter = (AB + BC + CA) / 2 = 24/2 = 12cm
Radius of the incircle = area/semi perimeter
= 24/12 = 2cm
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