Question

ABC is a triangle which angle A = 72° . The internal bisectors of angle B and C mention O. Find the value of angle BOC .​

Answer 1

Question

➡ ABC is a triangle which angle A = 72° . The internal bisectors of angle B and C meet O. Find the value of angle BOC .

Given : ABC is a ∆ which angle A = 72°

the internal bisectors of angle B ans C meet at O.

To find : value or angle BOC

Sol : if O in centre

then

angle BOC = 90 + angle A/2

$boc = 90 + 72 \div 2 \\ boc = 90 + 36 \\ boc = 126$

So BOC = 126०

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