Question

ABC is a variable triangle such that A is (1,2), B and C lie on the line y = x+J (where J is a variable), then the locus of the orthocenter of
triangle ABC is
2x-y=0
x+y=3
(x-1)2+y2 = 4
0 (x-1)2+(y-2)2=4

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Answer 1

Answer:

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Step-by-step explanation:

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