Question

abc is an equilateral triangle.D is any point on AC.Prove BD>AD​

Answer 1

Answer:

Consider the triangle △ADB.

∠BAD=60

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and ∠ABD<∠ABC⟹∠ABD<60

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Now, in a triangle, side opposite larger angle is greater than the side opposite smaller angle.

Hence, as BD is opposite ∠BAD, AD is opposite ∠ABD and we saw that ∠ABD<∠BAD=60

∘

,

∴BD>AD

Answer 2

Answer:

This is the right answer