Question

ABC is an equilateral triangle of side 0.03 metre charges of + 5 nc + 3 nanocoulomb and -5nc are placed at the corners A B and C respectively find the resultant force on charge placed at b

Answer 1

Answer:

The final resultant force is 0

Explanation:

To find the final resultant force need to find the f1 and f2. Then need to put the values in the formula: f1+f2.

Given: Side of triangle is 0.03 charges fora the all three sides 5,3,-5.

Find: Final resultant.

Calculation:

For f1:

$f1=K{q1q2}/r^{2}\\=K{(3)(-5)}/(0,03)^{2}\\\\=-15k/0.0009$

For f2:

$f1=K{q1q2}/r^{2}\\=K{(3)(5)}/(0,03)^{2}\\\\=15k/0.0009$

So the final value:

$f1+f2=15k/0.0009-15k/0.0009\\=0$

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