Question

abc is an equilateral triangle of side 10 units .find its altitude( height)

Answer 1

Step-by-step explanation:

AB=AC=BC=10 units

Draw AD perpendicular BC

angle ADB=90°

AD=10÷2=5 units

AB^2=AD^2+BD^2

10^2=AD^2+5^2

AD^2=100-25

AD^2=75

AD=√75

=5√3

=5×1.732

=8.66 units

Answer 2

Given Info :-

• The side of an equilateral triangle (ABC) is 10 units.

Explanation:-

We are asked to find –

• The height and the area of the triangle

Given that –

• The side of an equilateral triangle, a= 10 units.

We know that–

$\purple{\bigstar \; {\underline{\boxed{\bf{ Height_( Equilateral\: triangle) = √3/2 \times a}}}}}$    

$\longrightarrow \sf h =\dfrac{√3}{2} \times 10 \:units$

$\longrightarrow \sf h = √3\times 5$

$\longrightarrow \tt{\pink{\underline{\underline h= 5√3\: units }}}$

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• Area of an equilateral triangle = (√3/4) × a2 square units.

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