Question

ABC is an equilateral triangle of side 2a. Then its altitude is
(a) a√3 (b) √3 (0) 6√a (d) 2a​

Answer 1

Answer: (i) 2x² – 3x + 5 = 0 (ii) 3x² − 4√3x + 4 = 0 (iii) 2x² – 6x + 3 = 0 ... i) Two distinct real roots, if b² - 4ac >0 , then x= -b/2a + √D/2a &x= -b/2a - √D/2a. ii) Two ... roots will be –b/2a and –b/2a. -b/2a = -(-4√3)/2×3. = 4√3/6. = 2√3/3.

Step-by-step explanation:

Answer 2

Answer:

✓3a

Step-by-step explanation:

Equilateral triangle with side 2a

Area of equilateral triangle = ✓3/4 * side*side

Area of triangle = 1/2 * base * height

equating the above two formulaes

✓3/4 *2a*2a = 1/2* 2a* h

h= ✓3a