Question

ABC is an equilateral triangle. P and Q are 2 points on AB and AC respectively such that PQ is parallel to BC. If PQ =5cm , then area of triangle APQ is: ?​

Answer 1

SoluTion :-

$\sf {As\ PQ\ ||\ BC}\\\\\\\\\sf {\Rightarrow \Delta APQ\ {\raise.17ex\hbox{ \scriptstyle\sim }}\ \Delta ABC}\\\\\\\\\sf {\Delta APQ\ is\ also\ an\ equilateral\ triangle}\\\\\\\\\sf {\Rightarrow \Delta APQ=\frac{\sqrt{3} }{4} (5)^2}\\\\\\\sf {\Rightarrow\ \ \frac{25 \sqrt{3} }{4} cm^{2}}$