Question

∆ABC is an equilateral triangle. P is the point on side BC such that PC= 1/3 BC. If AB = 6cm , then find AP.

Answer 1

By the given statement, ABP forms a new triangle where AB = 6cm, BP = 4cm ([2/3]*6) ie BP is ⅔ of BC and Ang ABP = 60°

Therefore We can use

tan 60° = PA/BP

PA = tan 60° * BP

=√3 * 4

= 4√3 cm