∆ABC is an equilateral triangle.With each vertex of triangle as center.A circle is drawn with radius 4 cm.find area of the shaded region
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As we know that ABC is a equilateral triangle hence each angle is 60°
now area of shaded region= area of triangle-area of three sector
area of triangle = √3a²/4
= √3 x 8 x 8 / 4
= 16√3
area of one sector = 60/360(πr²)
= 1/6(π x 4 x 4)
= 1/6(16π)
area of 3 sector
= 1/2(16π) = 8π
now area of shaded region
16√3-8π
2.58 approx
I m not sure about the answer. so u can recheck it
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