ABC is an isoceles triangle with AB=AC.Draw AP is perpendicular BC to show that angle B is equal to angle C?
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IN Δ ABP and ACP
AP=AP
AB = AC(given)
∠APB = ∠APC = 90°
so by RHS rule ΔABP = ΔACP
⇒∠B = ∠C
OR
as AB =AC
∠B = ∠C ( angles opp. to equal sides are equal )
AP=AP
AB = AC(given)
∠APB = ∠APC = 90°
so by RHS rule ΔABP = ΔACP
⇒∠B = ∠C
OR
as AB =AC
∠B = ∠C ( angles opp. to equal sides are equal )
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