ABC is an isosceles right angled triangle in which angle C =90°. If AC= 5 cm, then AB2 is equal to:
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Answer:
is an isosceles right angle triangles having ∠C = 90°. If D is any point on AB, then AD2+BD2 is equal to
A) CD2
B) 2CD2
C) 3CD2
D) 4CD2
Correct Answer:
B) 2CD2
Description for Correct answer:
△ABC is a right angle triangle. In which ∠C=90∘ And D is a point on AB such that D is perpendicular on AB.
Let AC = BC = a
∴AB2=AC2+BC2=a2+a2
AB=a2
∴BD=AD=a2–√2=a2–√
Now In △ACD
=AC2=CD2+AD2
a2=CD2+a22
a2−a22=CD2
a22=CD2
CD2=a22
2CD2=a2
and AD2+BD2=(a2–√)2+(a2–√)2
=a2–√+a2–√=a2
∴2CD2=AD2+BD2
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