Question

ABC is an isosceles triangle, AB=AC=12 cm. BC=10 cm. Calculate the perpendicular distance from A to BC

Answer 1

Answer:

the perpendicular distance is 13 cm

Step-by-step explanation:

let the point where perpendicular of A is intersects = D

by pythagores ,

in triangle ABD ,

AD^2 = 12^2 +5^2

AD^2 = 144+25

AD= root 169

AD = 13 cm

Answer 2

Answer:

the perpendicular distance is 13 m