Abc is an isosceles triangle in ab is equal to ac p is any point in the interior of triangle abc such that angle abp is equal to angle acp prove that bp is equal to cp and ap bisect angle bac
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in ABC, ab=ac(given)
ap=ap(common)
angle abp=angleacp
so, by s.a.s abp is congruent to apc
so,bp=cp(c.p.c.t)
and ap bisect angle bac
ap=ap(common)
angle abp=angleacp
so, by s.a.s abp is congruent to apc
so,bp=cp(c.p.c.t)
and ap bisect angle bac
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Prakhar2908:
Wrong.
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