Question

ABC is an isosceles triangle in which AB=AC and AE bisects the exterior angle CAD at A. Prove that AE parallel to BC

Answer 1

because when two sides are equal than two opposite angles are equal than sum of two interiors angles is equal to its opposite exterior angles than the both angles are equal angle CEA =BCA .this is also known as alt.int.angle . Therefore,AE parallel to BC.

Answer 2

• Step-by-step explanation  : because when two sides are equal than two opposite angles are equal than sum of two interiors angles is equal to its opposite exterior angles than the both angles are equal angle CEA =BCA .this is also known as alt.int.angle . Therefore,AE parallel to BC