ABC is an isosceles triangle in which ab is equal to AC also D is the point such that BD is equal to CD prove that ad bisects angle A and angle d
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In triangle ABD and ADC
AB=AC
BD=D.C.
AD=AD (common)
therefore triangle AND _~triangle ADV
so AD bisected angle A
AB=AC
BD=D.C.
AD=AD (common)
therefore triangle AND _~triangle ADV
so AD bisected angle A
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