Math, asked by varshakhatiyan, 1 year ago

ABC is an isosceles triangle in which AC=BC .IF AB sq =AC sq .then prove that ABC is a right triangle​

Answers

Answered by sonabrainly
2

Answer:

Δ ABC is an isosceles triangle  with AC = BC , and AB² = 2AC²

To prove : ∠C = 90°

Proof :-

AB² = 2AC²

      = AC² + AC²

      = AC² + BC²                                  [ ∵ AC = BC ]

AB² = AC² + BC²     ----> (1)

From (1) , 

∠C = 90° [ by converse of Pythagoras theorem ]


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Answered by daisybaktha
1

Answer:

ABC is an isosceles triangle in which AC=BC .IF AB sq =AC sq .then prove that ABC is a right triangle​Step-by-step explanation:

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