ABC is an isosceles triangle in which AC=BC .IF AB sq =AC sq .then prove that ABC is a right triangle
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Δ ABC is an isosceles triangle with AC = BC , and AB² = 2AC²
To prove : ∠C = 90°
Proof :-
AB² = 2AC²
= AC² + AC²
= AC² + BC² [ ∵ AC = BC ]
AB² = AC² + BC² ----> (1)
From (1) ,
∠C = 90° [ by converse of Pythagoras theorem ]
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ABC is an isosceles triangle in which AC=BC .IF AB sq =AC sq .then prove that ABC is a right triangleStep-by-step explanation:
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