Question

solve for x,,;;,?,,,?​

Answer 1

Take LCM on the LHS (Left Hand Side), we get:

(2x-3 + 2x)/x(2x-3) = 1/(x-2)

Now cross multiplying, we get:

→ (4x - 3)(x - 2) = x(2x-3)

→ 4x² - 8x - 3x + 6 = 2x² - 3x

→ 2x² - 8x + 6 = 0

→ x² - 4x + 3 = 0

→ x² - 3x - x + 3 = 0

→ x(x-3) - 1 (x-3) = 0

→ (x+3) (x-1) = 0

→ x = -3, 1

Thankyou!!!

Answer 2

x= -3 , 1

hope it help u