Math, asked by pratiksha6864, 11 months ago

ABC is an isosceles triangle in which altitude be and CF are drawn to equal sides AC and ab respectively show that these attitudes are equal​

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Answered by mukul346274
12

Answer:

In triangle ABE and ACF

Angle A=Angle A ( Common)

AB = AC (Given)

Angle AEB= ANGLE AFC= 90°

By AAS criteria Triangle ABE is congruent to ACF

By CPCT BE = CF

Hope you like the answer.

Answered by arnab6778
5

Answer:

As ABC is an isoscalene triangle.

so,

AB = AC

, BF = CE

In triangle BFC and CEB,

BF = CE (proved above)

And, angle BFC =angle CEB=90°

BC =BC (common)

hence,

triangle BFC and triangle CEB are congruent by S.A.S criteria.

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