Question

ABC is an isosceles triangle in which angle BAC = 45° and BC= CA ,then find the value of angle ACB.​

Answer 1

The angle ACB is 45° vecauseby the property of isoceles said that opposite sides and opssite angle are equals

Answer 2

Since AC=BC

Therefore, <A=<B

<A+<B+<C=180°

45+45+<C=180°

<C=90°

Hope it helps:)