Question

∆ABC is an isosceles triangle in which Line AB = Line AC. D is the midpoint of base Line BC. Prove that ∆ABD is congruent to ∆ACD. If measure of angle B= (3x+10)° and measure of angle C = 70°, find the value of x.
Some Hints are in the attachment(The figure).



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Answer 1

Answer:

refer to attachment pls

Answer 2

Step-by-step explanation:

given ABC is isosceles triangle

=> /B =/C

D is midpoint of BC

=>BD = DC

3x+10 = 70

3x=70-10

x=60/3

x=20

B = 20

IN triangleABD and triangleACD

AB = AC (given)

B = C

BD = DC

by SAS congruency rule

triangle ABD congruent to triangle ACD