ABC is an isosceles triangle right angled at C. If AB square=98, what is the length of the other two sides?
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24
AB²=98
AC=BC. (since it is an isosceles triangle, two sides are equal)
by Pythagoras theorem,
AB² = AC² + BC²
we know AC = BC,
therefore substitute
AB² = AC² + AC²
98 = 2AC²
98/2 = AC²
49 = AC²
therefore,. AC = √49
AC = 7
AC = BC = 7
AC=BC. (since it is an isosceles triangle, two sides are equal)
by Pythagoras theorem,
AB² = AC² + BC²
we know AC = BC,
therefore substitute
AB² = AC² + AC²
98 = 2AC²
98/2 = AC²
49 = AC²
therefore,. AC = √49
AC = 7
AC = BC = 7
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8
Answer:
AB² = AC ²+ BC ²
98=2AC²
AC ²=98/2
AC ²=49
AC = √49
AC =7cm
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