Question

ABC is an isosceles triangle right angled at C Prove Ab2=2Ac2​

Answer 1

Answer:

Step-by-step explanation:

Given data :

Δ ABC is a right Δ and also isosceles triangle.,  

To prove:

AB²=2AC²,

Step 1:

Proof:

Here,  

Hypotenuse = AB

Also, as it is given that, ΔABC is isosceles,  

Step 2:

AC = BC   [equal sides of isosceles Δ]  

Using Pythagoras theorem,  

Step 3:

In Δ ABC, we have ;

AB²=AC²+BC²[AC=BC],

AB²=AC²+AC²,

Hence AB²=2 AC²,Proved.

Hope it helps.

Answer 2

Step-by-step explanation:

GIVEN THAT,

ABC is an isosceles triangle

By using the Pythagoras therom

HYPOTENUSE IS "AC".

WE KNOW THAT

(HYPO)²=SIDE²+ SIDE²

AC²=AB²+BC²

WE KNOW THAT THE HYPOTENUSE=2BASE

BC IS AN BASE

SO,THE BC IS WILL DIVIDE WITH AC

AC²/AC=AB²

AC²=AB²

SO PROVED

I HOPE U MAY understand