Question

ABC is an isosceles triangle right angled at C. Prove thet AB²=AC².

Answer 1

In △ABC,

By Pythagoras Theorem,

(AB)² =(AC)² + (BC)² ..(1)

Since, △ABC is an isosceles triangle,

∴ AC = BC ..(2)

∴ From (1) and (2),

(AB)² = 2(AC)² [henceproved]

Answer 2

$\large{\underline{\boxed{\sf{\blue{Answer :-}}}}}$

In △ABC,

By Pythagoras Theorem :-

• (AB)² =(AC)² + (BC)² ..(1)

Since,

△ABC is an isosceles triangle,

∴ AC = BC ..(2)

∴ From (1) and (2),

(AB)² = 2(AC)² [Hence Proved]