Question

ABC is an isosceles triangle right angled at C show that AB^2=2AC^2

Answer 1

In ∆ ABC,

According to the Pythagoras theorem,

${AB}^{2} = {AC}^{2} + {BC}^{2}$
Also, it is given that ∆ ABC is an isosceles triangle.
So, AB = AC

SO,

${AB}^{2} = {AC}^{2} + {AC}^{2} \\ = > {AC}^{2} = 2 {AC}^{2}$

Answer 2

Hope useful for your.