Question

if (1+cosA)(1-cosA)=3÷4,find the value of secA

Answer 1

(1+cosA)×(1-cosA) = 3/4

(1-cos²A)=3/4,

sin²A=3/4,

then

sinA=√3/2,

sinA=sin60°,

then

A=60°,


therefore

secA=sec60°,

secA=2

Answer 2

(1-cos²A)=3/4
sin²A=3/4
sinA=√3/2
Sin A=Sin60°
A=60°
secA=1/cosA
Sin60°=1/cos60°
=1/1/2
SecA=2
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