if (1+cosA)(1-cosA)=3÷4,find the value of secA
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Answered by
10
(1+cosA)×(1-cosA) = 3/4
(1-cos²A)=3/4,
sin²A=3/4,
then
sinA=√3/2,
sinA=sin60°,
then
A=60°,
therefore
secA=sec60°,
secA=2
(1-cos²A)=3/4,
sin²A=3/4,
then
sinA=√3/2,
sinA=sin60°,
then
A=60°,
therefore
secA=sec60°,
secA=2
Answered by
5
(1-cos²A)=3/4
sin²A=3/4
sinA=√3/2
Sin A=Sin60°
A=60°
secA=1/cosA
Sin60°=1/cos60°
=1/1/2
SecA=2
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sin²A=3/4
sinA=√3/2
Sin A=Sin60°
A=60°
secA=1/cosA
Sin60°=1/cos60°
=1/1/2
SecA=2
please mark it brainlist
please bro
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